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What Is G2 Mathematics | Why Squaring a Negative Substitution Needs Brackets

Three learners review open books together at a classroom table, with stacks of textbooks, stationery and a whiteboard in the bright room.

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If the minus sign seems to move while squaring, begin with the first four chapters. If your confusion is about the difference between −x² and (−x)², use Sections 6 and 7. If the mistake appears only on a calculator or in a quadratic graph, use the later chapters and the mixed practice clinic.

Full worked substitution · 21 solved checks · Mathematics hub

When x is negative, substitute the whole value in brackets before applying exponents. With x = −3, x² means (−3)² = 9. But −x² means −((−3)²) = −9. These expressions are not interchangeable, and a calculator cannot decide which one the question intended if the input is ambiguous.

Brackets preserve the distinction between a sign belonging to the substituted value and a minus operation already present in the formula. The dependable sequence is to copy the expression, insert the complete value, perform powers, multiply coefficients and combine terms. That process matters for linear expressions, quadratic graphs, coordinates and more advanced algebra.

This G2 Mathematics guide explains a foundation found across numerical operations and algebra. SEAB’s 2027 G2 Mathematics K210 syllabus provides the official assessment framework, while the examples below include clearly identified extensions. Follow the student’s school programme for the exact topics and presentation conventions required.

SECTION 2 OF 30

Quick read

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A power applies to its base. The base in (−4)² is negative four, giving sixteen; the base in −4² is positive four, which is squared before the outside minus makes negative sixteen. Similarly, for x = −4, the expression −x becomes positive four, while −x² becomes negative sixteen.

Replace x with its complete bracketed value first. Check the sign of every term, including subtraction of a negative. If an equivalent expanded form exists, use it for an independent calculation. Never assume that the sign of the input dictates the sign of the whole function.

SECTION 3 OF 30

1. Substitution replaces a variable with its complete value

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To substitute means to replace every occurrence of a variable with a stated number or expression. When the value is negative, it includes a sign that must remain attached to it. Brackets make that value one complete unit. A student who writes x = −3 but then silently uses 3 has changed the question before beginning any calculation.

In x² + 2x with x = −3, replace each x with (−3). The expression becomes (−3)² + 2(−3), equal to nine minus six, or three. The working has no ambiguity about which sign belongs to which quantity.

The central action is not to introduce brackets randomly but to preserve the grouping specified by substitution. The sign is part of the number being inserted.

Write the value in brackets at each occurrence first; only after that should you apply powers, multiplication and addition in the correct order.

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SECTION 4 OF 30

2. Why (−3)² equals positive nine

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Squaring means multiplying a number by itself. When the entire factor is negative, the product contains two negative factors and is positive. The brackets tell us that the base of the exponent is negative three, rather than the positive three with an outside minus sign.

(−3)² = (−3) × (−3) = 9. Likewise, (−7)² = 49. This works because the product of two negative numbers is positive, not because the negative sign has been erased from the original number.

Checking the multiplication directly is more robust than memorising ‘a square is positive’ without knowing what is being squared. Zero also has square zero.

Expand the power into repeated factors at least once when learning. It reveals which signs are included in the operation.

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SECTION 5 OF 30

3. Why −3² is negative nine under the usual convention

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In ordinary school algebra, a power binds to its base before an outside unary minus is applied. Therefore −3² is read as −(3²), not (−3)². The two expressions contain the same characters arranged in different groups, but they represent different operations.

The expression −3² means negative of three squared, which is −9. By contrast, (−3)² means negative three multiplied by negative three, which is 9. Without parentheses, a learner can easily substitute the wrong one.

Calculator input styles can vary, so typing a negative value without brackets may not reliably communicate the intended mathematics. The written expression is the source of truth.

Ask ‘what is the base of the exponent?’ If the intended base is negative, place the negative value in brackets.

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SECTION 6 OF 30

4. Full solution: evaluate 2x² − 3x + 1 at x = −2

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Begin by writing the original polynomial exactly. Identify the three terms and the requested substitution. Replace x with (−2) in every occurrence, producing 2(−2)² − 3(−2) + 1. At this stage the numbers have not been simplified, so signs are still available for inspection.

Next calculate the power: (−2)² = 4. Multiply to obtain 2 × 4 − (−6) + 1 = 8 + 6 + 1 = 15. An independent check is to graph or tabulate the quadratic at x = −2 or to recalculate its terms separately.

A common wrong answer arises when a student treats (−2)² as −4. That mistake changes the first term from plus eight to minus eight and can shift the final answer by sixteen.

Separate substitution, indices, multiplication and collection onto distinct lines until the method becomes reliable.

StageWorking
Original2x² − 3x + 1, x = −2
Substitute2(−2)² − 3(−2) + 1
Power2 × 4 − 3(−2) + 1
Multiply8 + 6 + 1
Answer15

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SECTION 7 OF 30

5. Odd powers retain the sign of a negative base

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Repeated multiplication of a negative number alternates in sign: an even number of negative factors gives a positive product, while an odd number leaves a negative product. The sign pattern depends on the parity of the exponent, provided the base includes the negative sign.

(−2)³ = (−2)(−2)(−2) = −8, whereas (−2)⁴ = 16. The first contains three negative factors; the second contains four. The value does not alternate because calculators are unpredictable but because of multiplication rules.

A negative index means something different from a negative base. These two uses of the minus symbol should not be merged.

Before computing, predict whether the result should be positive or negative. A sign prediction catches many arithmetic errors early.

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SECTION 8 OF 30

6. Distinguish the variable x from the expression −x

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The symbol −x means the additive inverse of whatever number x represents. It does not mean x itself must be negative. If x is already negative, then −x is positive. The sign in the expression is an operation, while the sign attached to the substituted value describes that value.

If x = −4, then −x = −(−4) = 4. But x² = (−4)² = 16 and −x² = −16. In contrast, (−x)² = (−(−4))² = 4² = 16. These expressions must be read one by one.

The distinction matters in algebraic manipulation, graph coordinates and formulas involving opposite directions. It also explains why double negatives are not automatically errors.

Rewrite each negation with clear brackets before simplifying. Never decide the sign only from counting how many minus marks appear in a line.

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SECTION 9 OF 30

7. Why (−x)² and −x² are generally different

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Brackets determine whether the negative operation sits inside or outside the square. For any real x, (−x)² = x² because the two negative factors cancel. Meanwhile −x² = −(x²), which is nonpositive for every real x. The expressions agree only when x equals zero.

With x = 3, (−x)² = (−3)² = 9, whereas −x² = −(3²) = −9. With x = −3, the same outputs occur: (−x)² = 9 and −x² = −9. The meaning of the expression, not the original sign of x, controls the result.

This is a strong counterexample to the idea that parentheses around a negative base are optional decoration. They change the algebraic object being squared.

Whenever a power follows a bracket, point to the full contents of the bracket as its base. That habit generalises to more complicated formulas.

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SECTION 10 OF 30

8. A coefficient multiplies the entire substituted value

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In a term such as 5x, the coefficient five multiplies the value of x. With x negative, the product becomes negative for a positive coefficient. If the coefficient is also negative, multiplying two negatives gives a positive value. Keeping brackets around the variable value makes both cases easy to inspect.

For x = −6, 5x = 5(−6) = −30, while −5x = (−5)(−6) = 30. These are different terms even though only one extra minus sign appears.

A student who removes the negative value from the bracket early may accidentally treat −5x as negative five times positive six and obtain −30, the wrong sign.

Mark the coefficient and the inserted value as two factors before multiplying. Then determine the sign and only afterward the magnitude.

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SECTION 11 OF 30

9. The subtraction symbol can precede a negative value

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An expression a − x means subtract the current value of x. If x is negative, subtracting it is equivalent to adding its positive opposite. The subtraction sign in the formula and the negative sign in the substituted number serve different roles; writing them with brackets preserves both.

With x = −5, 8 − x becomes 8 − (−5) = 13. The result is larger than eight, which is a useful reasonableness prediction. The wrong result 3 comes from treating the value as positive five.

Subtraction of a negative number is also a movement to the right on a number line. This interpretation is helpful when symbol manipulation becomes confusing.

Ask whether subtracting a negative quantity should increase or decrease the starting number. The numerical answer should match that prediction.

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SECTION 12 OF 30

10. Brackets protect signs inside squared binomials

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When the power applies to a whole bracket such as (x − 2)², substitution must preserve the bracket, then simplify inside it, then square the result. The square does not apply separately to x and to two. Students who ignore the whole bracket may omit the cross term or square a sign incorrectly.

If x = −1, then (x − 2)² = (−1 − 2)² = (−3)² = 9. It is not (−1)² − 2² = −3. Nor is it −(1 − 2)² without showing how the values were grouped.

A binomial square can be expanded, but direct substitution into the original bracket often saves work and reduces errors.

Evaluate the contents of the bracket first when the expression is given in bracket form. Keep the outer exponent visible until the inside has become one number.

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SECTION 13 OF 30

11. Substitution into a formula with a leading minus

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Some formulas deliberately negate a squared quantity, such as y = −x² + 4. The minus sign outside the power changes the output after squaring. If x is negative, the squared contribution still becomes positive before the leading minus reverses its sign.

For x = −3, y = −(−3)² + 4 = −9 + 4 = −5. If a student rewrites the first part as (−(−3))², the result becomes positive nine and the formula’s meaning has been changed.

This distinction explains why y = x² and y = −x² open in opposite vertical directions even though both use squared x values.

Copy the original formula and highlight where the negative sign sits relative to the exponent. Moving it across brackets changes the function.

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SECTION 14 OF 30

12. Negative coordinates require the same careful substitution

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Coordinate geometry often asks whether a point lies on a given curve. The x coordinate might be negative, while the y coordinate can be positive or negative depending on the formula. The test is a substitution into the defining equation, not a judgment based on how the point looks in a sketch.

Does (−2, 5) lie on y = x² + 1? Substitute x = −2: y = (−2)² + 1 = 5, so yes. Does (−2, −3) lie on the same curve? No, because the calculated y value is five.

An ordered pair is a matched claim about x and y. Correctly calculating the first component alone does not verify the whole point.

Check the computed output against the stated y coordinate and show the equality explicitly.

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SECTION 15 OF 30

13. Even powers explain symmetry in basic quadratic graphs

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For a function of the form y = x², replacing x with its opposite does not change the output. This happens because the negative sign disappears when the whole negative base is squared. The graph is therefore symmetrical about the y-axis. The symmetry comes from algebra rather than from artistic smoothness of a sketch.

At x = 3, y = 9. At x = −3, y = (−3)² = 9. The points (3,9) and (−3,9) have the same height but lie on opposite sides of the vertical axis.

The symmetry claim here applies to x² and other even functions of the same kind, not to every quadratic with additional linear terms.

Create a small table at x values −3, −2, −1, 0, 1, 2, 3 and compare outputs before sketching a graph.

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SECTION 16 OF 30

14. A linear term can break symmetry about the y-axis

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The expression x² + x includes both an even-power part and a first-power part. Replacing x with −x changes the sign of the linear contribution but not the squared contribution. Therefore its graph generally is not symmetrical about the y-axis, even though it is still a parabola with another vertical axis of symmetry.

For x = 2, x² + x equals six. For x = −2, it equals four minus two, or two. The difference is caused by the linear x term. The axis of symmetry is x = −1/2, not x = 0.

A student who assumes every squared expression gives identical outputs for opposite inputs may overlook the rest of the formula.

Inspect the whole function, not just the highest power. Symmetry of one term need not be symmetry of their sum.

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SECTION 17 OF 30

15. Fractional negative substitutions work by the same rule

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A negative fraction is one complete numerical value. Its sign belongs to the numerator or to the overall fraction, and the denominator must remain nonzero. Squaring the whole negative fraction produces a positive result; applying a minus outside the square produces the negative of that result.

With x = −1/2, x² = (−1/2)² = 1/4, while −x² = −1/4. For y = 3x² − x, substitute to obtain 3/4 − (−1/2) = 3/4 + 1/2 = 5/4.

Fractional arithmetic can reveal whether a student has preserved both the sign and denominator correctly. A decimal conversion is not compulsory.

Keep the entire fraction inside brackets, then square numerator and denominator consistently.

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SECTION 18 OF 30

16. Decimal negative substitutions also require grouping

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Negative decimals work under the same exponent and multiplication rules as negative integers. A calculator might make the arithmetic faster, but it does not resolve ambiguous notation. Brackets remain important both on paper and when entering a calculation into a device.

For x = −0.4, x² = 0.16, while −x² = −0.16. Evaluate x² + x = 0.16 − 0.4 = −0.24. The final answer is negative even though the squared term is positive.

An answer can combine positive and negative contributions. Predicting the sign of each term is more reliable than assuming a polynomial containing a square must produce a positive total.

Write the values of the individual terms before combining them. If the final result is unexpected, the term list helps locate the error.

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SECTION 19 OF 30

17. Negative indices are not negative bases

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The notation x⁻² places a minus sign in the exponent rather than in the base. For nonzero x, it means 1/x², not negative x squared. By contrast, (−x)² squares the negative of x. These notations look similar in a crowded line of working but encode different operations.

With x = −2, x⁻² = 1/(−2)² = 1/4. The expression −x² = −4, and (−x)² = 4. Three related-looking expressions yield three different values: a quarter, negative four and positive four.

Negative indices require nonzero bases for the reciprocal expression. That restriction is separate from the sign of the base itself.

Circle the exponent and identify whether its minus sign is superscripted or placed before the entire term.

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SECTION 20 OF 30

18. The principal square root is a separate question

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The symbol √a denotes the principal nonnegative square root when working with nonnegative real a. Therefore √9 equals three, while the equation x² = 9 has two solutions, positive and negative three. Mixing substitution with square-root interpretation can create a sign error at a later stage even if the original square was evaluated correctly.

If x = −3, then x² = 9 and √(x²) = √9 = 3. This equals the absolute value of x, not x itself. The valid identity for real x is √(x²) = |x|.

The expression √(x²) can lose the original sign, which is why a student cannot simply cancel the square and root to obtain x for every real value.

Keep square-root evaluation and solving a quadratic equation as separate operations. Ask whether the task seeks one principal value or all solutions.

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SECTION 21 OF 30

19. A negative input does not force a negative output

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The sign of the value of a function depends on the full expression, not merely the sign of its input. Squares, coefficients and constants interact. This is particularly important when students inspect a graph or a word problem and wrongly expect all negative x-values to correspond to negative y-values.

For y = x² − 5, x = −1 gives y = 1 − 5 = −4, while x = −3 gives y = 9 − 5 = 4. Both inputs are negative, yet one output is negative and the other positive.

The change arises from different squared magnitudes. A number farther from zero has a larger square, regardless of its sign.

Test two negative values rather than assuming a sign rule. A sign prediction should follow the expression, not the variable alone.

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SECTION 22 OF 30

20. Check a substitution by expanding an equivalent form

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An independent algebraic check can help confirm substitution results when the expression has two equivalent forms. Expanding or factorising correctly gives a new route to the same number. However, the check must preserve equivalence, so a student should not use an unverified shortcut as the checking method.

Take (x − 3)² with x = −2. Direct substitution gives (−5)² = 25. Expand first to x² − 6x + 9, then substitute: 4 − 6(−2) + 9 = 4 + 12 + 9 = 25. The two paths agree.

The successful comparison tests brackets, the cross term and arithmetic. It is stronger than pressing the same calculator keys twice in the same order.

Use different mathematically equivalent methods for checking when time permits. Repeatedly copying the same error is not an independent check.

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SECTION 23 OF 30

21. A calculator needs explicit parentheses

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Digital tools follow input conventions that can differ in how they accept a leading minus. Some devices distinguish a negative-value key from a subtraction key, while text-based software uses its own precedence rules. To communicate the intended squared negative base reliably, enter the grouped expression explicitly.

To evaluate (−3)², enter the negative three as a parenthesised base and then apply the square. To evaluate −3² under the usual algebraic convention, square three first and apply an outside negative. The mathematical targets are nine and negative nine respectively.

The distinction is one of notation and grouping, not a claim that calculators are unreliable in general. Explicit input simply reduces a predictable source of ambiguity.

Match the display expression to the line of written working. If it displays a different grouping, correct the input before accepting the output.

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SECTION 24 OF 30

22. Substitution works inside formulas for area and rates

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Algebraic formulas are interpreted in context. A negative length or negative area might be impossible in a geometry model, even though substituting the number into a polynomial is algebraically permitted. Other contexts, such as signed displacement or profit change, may meaningfully allow negative values. The model’s domain is distinct from the arithmetic rule.

A square with side x has area x², but a physical side length must be nonnegative. Substituting x = −3 produces nine algebraically, yet ‘a side of negative three centimetres’ is not a valid physical square in this model.

This distinction prevents a correct arithmetic substitution from being mistaken for a realistic scenario. A mathematical function can have a wider algebraic domain than its chosen application.

State the context’s admissible values separately from the calculation. Do not use a physically impossible input as a real measurement conclusion.

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SECTION 25 OF 30

23. Spot the first unsupported step in an incorrect answer

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An incorrect final value may come from substituting without brackets, applying the exponent to the wrong base, mishandling subtraction of a negative number or collecting unlike terms incorrectly. These are different skills. Effective revision begins with locating the first line that no longer follows from the original expression.

A student is asked to find 2x² − x for x = −3 and writes 2(−3²) − (−3) = −18 + 3 = −15. The first error is changing (−3)² into −3². Correct it to 2(9) + 3 = 21. The subtraction step itself was not the problem.

Correction should target the point where the expression changed meaning, not simply replace the final answer with twenty-one.

Ask students to compare the original, the substituted line and the first simplified line. This three-line audit is often more useful than a long general lecture about carelessness.

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SECTION 26 OF 30

24. Use a sign prediction as a second check

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Before computing an expression, identify whether each term should be positive, negative or zero under the stated substitution. A sign prediction may not determine the final answer, but it can rule out some errors immediately. It also develops number sense beyond mechanical calculator work.

For 3x² + 2x − 1 at x = −2, the squared contribution is positive twelve, the linear contribution is negative four, and the constant is negative one. The total is seven. A learner who obtains negative seventeen has probably misplaced the sign around x².

A prediction is a diagnostic, not a substitute for arithmetic. Positive and negative terms may cancel or outweigh one another.

Create a small three-column table for ‘term’, ‘expected sign’ and ‘calculated value’ on mixed-sign algebra questions.

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SECTION 27 OF 30

25. Connect the method to later algebra and graphs

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Brackets around substituted negative values matter in polynomial equations, coordinate geometry, quadratic graphs, functions, numerical patterns and many future Mathematics topics. The aim is not simply to remember a single convention about minus signs, but to preserve complete expressions as mathematical objects.

The 2027 SEC G2 Mathematics K210 syllabus includes negative numbers, indices and algebraic work. The How Mathematics Works hub connects these concepts to G3 graphs and problem solving, while the Clementi Secondary 1 Mathematics reference explains the value of tracing errors to the first unstable step.

An extension may use a more elaborate function than a current school assignment. Use the official syllabus and the student’s teacher to identify the assessed scope for the year.

Strengthen the simplest case first: x = −3 inside x² and −x². Then move to binomials, formulas, coordinates and mixed expressions.

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SECTION 28 OF 30

26. A compact routine that stays reliable under time pressure

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A good substitution workflow is short enough to use in assessments: copy the original expression; replace each variable with its whole bracketed value; evaluate the brackets and exponents; multiply coefficients; combine signed terms; and check the final value by a second route if needed. Missing the second step is often where errors begin.

For y = (x + 4)² − 2x with x = −5, write y = ((−5) + 4)² − 2(−5) = (−1)² + 10 = 11. The sign of the input was preserved in both places, and the squared bracket was evaluated only after simplifying its interior.

One useful final check is to predict whether the second term −2x should add or subtract when x is negative. Here it adds ten, matching the working.

Show enough steps to make grouping visible. Clear working can remain concise when every transition is justified.

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SECTION 29 OF 30

Practice clinic: 21 solved substitutions

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Cover each answer before evaluating the expression. Copy the original, substitute the negative number in brackets, predict the sign of each term and calculate. After checking the solution, name the precise source of any error: the base of a power, the coefficient, the subtraction sign or an expression inside parentheses.

Case 1. Evaluate x² for x = −6.

36 because (−6)(−6) = 36.

The entire negative number is the base.

Case 2. Evaluate −x² for x = −6.

−36, the negative of the squared value.

The leading minus applies outside the square.

Case 3. Evaluate (−x)² for x = 6.

36 because (−6)² = 36.

The minus is inside the squared bracket.

Case 4. Evaluate (−x)² for x = −6.

36 because −x = 6 and 6² = 36.

An opposite of a negative can be positive.

Case 5. Evaluate x³ for x = −2.

−8.

Three negative factors give a negative product.

Case 6. Evaluate x⁴ for x = −2.

16.

Four negative factors give a positive product.

Case 7. Evaluate 5x for x = −3.

−15.

Positive coefficient times negative value is negative.

Case 8. Evaluate −5x for x = −3.

15.

Negative coefficient times negative value is positive.

Case 9. Evaluate 7 − x for x = −2.

9.

Subtracting negative two is adding two.

Case 10. Evaluate x² + 2x for x = −3.

3, since 9 − 6 = 3.

The squared and linear terms have different signs.

Case 11. Evaluate 2x² − 3x + 1 for x = −2.

15, from 8 + 6 + 1.

Keep every negative substitution in brackets.

Case 12. Evaluate (x − 2)² for x = −1.

9.

Simplify the bracket to −3 before squaring.

Case 13. Evaluate (x + 4)² for x = −5.

1.

The entire bracket evaluates to −1.

Case 14. Evaluate x² − 5 for x = −1.

−4.

A positive square does not guarantee a positive function output.

Case 15. Evaluate x² − 5 for x = −3.

4.

The squared magnitude can outweigh a negative constant.

Case 16. Test point (−2, 5) on y = x² + 1.

The point lies on the curve.

Substituting x = −2 produces y = 5.

Case 17. Evaluate x⁻² for x = −2.

1/4.

A negative exponent denotes a reciprocal, not a negative base.

Case 18. Evaluate √(x²) for x = −3.

3.

The principal square root of nine is nonnegative.

Case 19. Evaluate 3x² − x for x = −1/2.

5/4.

Three quarters plus one half equals five quarters.

Case 20. Evaluate (x − 3)² for x = −2 by two methods.

25 directly, or 4 + 12 + 9 after expansion.

Equivalent forms provide independent confirmation.

Case 21. Evaluate (x + 4)² − 2x for x = −5.

11.

The first bracket squares to one and −2x contributes ten.

The best review is not to repeat the same problem five times. Choose a contrasting case that changes only one mathematical feature. Compare (−3)² with −3², then compare x² with −x² at a negative x, then add a linear term. Each comparison protects a different part of the expression.

SECTION 30 OF 30

Frequently asked questions

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Is a negative number squared always positive?

The square of a nonzero negative real number is positive when the entire negative number is the base, for example (−3)² = 9. Zero squared is zero.

Why does −3² differ from (−3)²?

By the standard order of operations, −3² means −(3²) = −9, while (−3)² means (−3) × (−3) = 9. The parentheses change the base.

Does −x mean that x is negative?

No. It means the opposite of the value of x. If x = −4, then −x = 4.

Can a negative x give a positive y in a quadratic?

Yes. For y = x², both x = −3 and x = 3 produce y = 9. The full expression determines the output sign.

Should I always use brackets when substituting?

Brackets are particularly important with negative values and compound expressions because they preserve the exact quantity being substituted. They prevent the exponent or coefficient from applying to the wrong base.

Is this guide the entire G2 Mathematics syllabus?

No. It explains a specific foundation and includes optional extensions. For exact assessed scope refer to SEAB’s 2027 K210 syllabus and your school’s teaching programme.

The 2027 G2 syllabus directory is the official reference for examinations. For linked teaching material explore the G1/G2/G3 Mathematics explainer directory, the Clementi Secondary 1 Mathematics reference and why negative indices mean reciprocals.

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