Did you know? A question with fractions can be easier than it looks once every term is written clearly. Many students already know how to solve 7x − 6 = 36; what slows them down is recognising that a fractional equation can sometimes be turned into exactly that.
Quick answer for Bukit Timah parents: the 2027 SEC G1 Mathematics K110 syllabus includes simple fractional equations that reduce to linear equations. Students need to identify the denominators, use a common multiple to remove the fraction bars safely, expand any brackets and check that the final value works in the original equation.
Why fractions make a simple equation look unfamiliar
Compare x + 4 = 10 with x/3 + (x − 2)/4 = 3. Both are equations because there is an equals sign. The second has fractions, so the first useful move is to find a number that clears the denominators without changing the equality.
We can multiply both sides of an equation by the same non-zero number. If several terms appear on one side, every term must be included. That is the central idea behind clearing denominators.
Example 1: remove two different denominators
Solve x/3 + (x − 2)/4 = 3. The denominators are 3 and 4. Their lowest common multiple is 12. Multiply every term on both sides by 12.
The result is 4x + 3(x − 2) = 36. Expand the bracket: 4x + 3x − 6 = 36. Combine like terms: 7x − 6 = 36. Add 6: 7x = 42. Divide by 7 to get x = 6.
Now check against the original question: 6/3 + (6 − 2)/4 = 2 + 1 = 3. It agrees. We have not merely found a neat number; we have confirmed that it satisfies the original equation.
Example 2: when the unknown is in the denominator
Solve 3/(x − 2) = 6. Because the denominator cannot be zero, x ≠ 2. Multiply both sides by x − 2, which is permitted for values in the equation’s domain. We get 3 = 6(x − 2).
Expand: 3 = 6x − 12. Add 12: 15 = 6x. Divide by 6: x = 2.5. Check: 3/(2.5 − 2) = 3/0.5 = 6. The value works and does not make the original denominator zero.
This is why a tutor should ask, “Is there any value of x that would make the denominator zero?” It is not enough to cross-multiply mechanically and forget that a fraction must be defined.
Example 3: a common multiple is faster than decimals
Solve (x + 3)/5 = (x + 1)/3. Multiply both sides by 15: 3(x + 3) = 5(x + 1). Expand: 3x + 9 = 5x + 5. Rearrange to obtain 4 = 2x and therefore x = 2.
Check by substituting x = 2: the left side is (2 + 3)/5 = 1, and the right side is (2 + 1)/3 = 1. No decimal approximations were needed.
Five mistakes that cost marks
- Multiplying only one fraction: clearing denominators means multiplying every term by the common multiple.
- Dropping a bracket: 3(x − 2) means 3x − 6, not 3x − 2.
- Moving a term without keeping balance: describe adding or subtracting from both sides instead of relying on a vague ‘move across’ rule.
- Ignoring zero denominators: check whether the candidate solution makes any original fraction undefined.
- Skipping the check: substitute into the original fractional equation, not only the simplified line.
What K110 actually expects
The official SEAB 2027 G1 Mathematics K110 syllabus explicitly includes simple fractional equations that can be reduced to linear equations in section N7, Equations. The published examples include equations with denominators 3 and 4 and one with a variable in a denominator. These are not an invitation to import every advanced rational-equation technique from higher subject levels.
The 2027 G1 school-candidate syllabus list shows Mathematics as K110, with 4046 listed for reference to 2026 and earlier. Parents should use the student’s correct examination year and subject code, especially when selecting revision papers.
A five-minute practice for home
Try x/2 + (x + 1)/3 = 5. Multiply every term by 6: 3x + 2(x + 1) = 30. Expand to get 5x + 2 = 30, so x = 28/5 = 5.6. Check: 5.6/2 + 6.6/3 = 2.8 + 2.2 = 5.
If your child gets the answer but cannot explain why the 6 is applied to all three terms, ask for an explanation before assigning another sheet. If they know the common multiple but repeatedly mishandle brackets, practise expansions separately and then return to the full equation.
How a tutor can make the lesson more effective
A useful small-group lesson begins with a diagnosis: is the issue fraction arithmetic, multiplication across equality, expanding brackets or checking solutions? The unchanged eduKateSG Clementi three-pupil tutorial reference illustrates close feedback for an earlier-secondary service. Please confirm directly whether Secondary 4 G1 tuition is available and the current learning arrangement; that original page is not proof of a specific timetable or place.
Frequently asked questions
Do G1 students have to solve equations with fractions? Yes. The 2027 K110 syllabus explicitly includes simple fractional equations reducible to linear equations.
Is cross-multiplication always safe? It can be useful when two fractions are equal and their denominators are non-zero, but clearing a common denominator is often clearer for sums of several terms.
Will a calculator solve the reasoning problem? No. It can check arithmetic, but the student must write a valid sequence of algebraic steps.
Related Secondary 4 G1 Mathematics reading
Continue with multiplying and dividing algebraic fractions, changing the subject of formulae and repairing repeated algebra mistakes.