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Choose a route or read from the beginning. All teaching chapters stay open; the grouped index below is expandable.
Name the volume
Chapters 1–2. Separate space in the rock from gas at a reference state.
Build the conversion
Chapters 3–5. Derive Bg and follow a complete gas-in-place calculation.
Change the conditions
Chapters 6–7. Test pressure, reference conditions and phase limits.
Check the evidence
Chapters 8–10. Audit assumptions, practical inputs and common questions.
Practise and continue
Chapters 11–12. Solve changed cases and choose further reading.
Full chapter index · Practice and worked checks · Petroleum Geology subject root
A gas-in-place estimate can contain two very different cubic metres. One describes the space occupied by gas underground. The other describes the volume that the same amount of gas would occupy at stated reference conditions.
The distinction matters before any multiplication begins. A large change in reported volume may describe a change of pressure, temperature or reporting basis, with no change in the amount of gas. This guide builds that conversion, then shows where it stops being sufficient.
It extends the Petroleum Geology subject guide with a fictional single-phase gas calculation. None of the numerical inputs represents a real field.
Chapter index
Name the volume · Chapters 1–2
1. Give every gas volume a state
2. Separate pore space from the gas amount
Build the conversion · Chapters 3–5
3. Derive the gas formation volume factor
4. Calculate one complete fictional example
5. Let units choose multiplication or division
Change the conditions · Chapters 6–7
6. Change the pressure or the reporting basis
7. Know when a two-state gas ratio is insufficient
Check the evidence · Chapters 8–10
8. Catch the mistakes before trusting the total
9. Build an evidence trail for the estimate
10. Questions that clarify the volume basis
Practise and continue · Chapters 11–12
11. Practise with changed conditions
12. Continue from storage to defensible decisions
Imagine following a sealed parcel of gas from a high-pressure state to a much lower-pressure state. Its volume can increase even though no molecules enter the parcel. Volume alone is therefore an incomplete description of its amount.
Write Vres for gas volume at the stated reservoir pressure and temperature. Write Vstd for the volume of the same amount of gas at the specified standard pressure and temperature. The subscripts are part of the meaning, even when both volumes use m³.
Here we choose pstd = 101,325 Pa absolute and Tstd = 288.15 K. These are this example’s reporting conditions. A document using another standard temperature or pressure needs another conversion. The word “standard” does not remove the need to state the numbers.
A geological model first estimates rock volume. Porosity φ gives the pore fraction; gas saturation Sg gives the gas-filled fraction of those pores. In a uniform model, gas-filled reservoir volume is Vres = A × hnet × φ × Sg.
A is area and hnet is net reservoir thickness. If net thickness has already excluded non-reservoir intervals, multiplying again by a net-to-gross fraction counts the same exclusion twice. Gas saturation is a fraction of pore volume, not a fraction of all rock volume.
This step describes occupied space under reservoir conditions. It does not yet express standard gas volume. It also does not establish connectivity, deliverability, a recovery fraction or commercial reserves.
For the same gas amount n in a single phase, use pV = ZnRT. Pressure p and temperature T are absolute; Z is the dimensionless gas compressibility factor. Z accounts for departure from the ideal-gas relation and is not the same quantity as isothermal compressibility.
At the two states, Vres = Zres nR Tres / pres and Vstd = Zstd nR Tstd / pstd. Dividing cancels nR:
Bg = Vres / Vstd = (Zres / Zstd) × (Tres / Tstd) × (pstd / pres).
With identical volume units, Bg is numerically a volume ratio. Preserve the labels “reservoir m³ per standard m³” in the working. They tell you which direction the conversion runs.
SLB’s gas formation volume factor definition uses this reservoir-to-standard volume ratio. The King Saud University reservoir-fluid lecture develops it from the gas relation. Its field-unit constants belong to its stated pressure, temperature and volume conventions; they are unnecessary in the consistent SI calculation here.
Take area 1,500,000 m², net thickness 10 m, porosity 0.25 and gas saturation 0.80. Assume those values describe a uniform, gas-bearing volume with no oil phase. Let pres = 20,000,000 Pa absolute, Tres = 350 K, Zres = 0.90 and Zstd = 1.00.
| Step | Calculation | Result and basis |
|---|---|---|
| Net rock volume | 1,500,000 × 10 | 15,000,000 m³ rock |
| Pore volume | 15,000,000 × 0.25 | 3,750,000 m³ pores |
| Gas-filled pore volume | 3,750,000 × 0.80 | 3,000,000 reservoir m³ gas |
| Bg | 0.90 × (350 / 288.15) × (101,325 / 20,000,000) | About 0.005538 reservoir m³ per standard m³ |
| Standard gas volume | 3,000,000 / Bg | About 542 million standard m³ |
Use the unrounded factor in the last calculation. The large standard volume is consistent with expansion from the much higher reservoir pressure. It is not a claim that producing the field would deliver that whole amount.
CHAPTER 5 OF 12 · Build the conversion
5. Let units choose multiplication or division
From Bg = Vres / Vstd, rearrange to Vstd = Vres / Bg. Dividing reservoir m³ by reservoir m³ per standard m³ leaves standard m³. Multiplying would leave the wrong labelled basis.
Reverse the calculation as a check: approximately 542 million standard m³ multiplied by Bg returns approximately 3 million reservoir m³. The two reported volumes represent the same modelled gas amount at different states.
It is tempting to remember that gas “expands” and choose an operation from that word. A stronger habit is to write the defining ratio and cancel labelled units. That method still works when another source defines a conversion factor in the opposite direction.
CHAPTER 6 OF 12 · Change the conditions
6. Change the pressure or the reporting basis
First compare two hypothetical reservoirs with the same gas-filled pore volume, temperature and Z but pressures of 20 MPa and 10 MPa absolute. Holding those other inputs fixed, halving pressure doubles Bg. The lower-pressure case then contains half as much standard gas volume in the same underground space.
That is a comparison of different gas inventories. It is not a prediction that a sealed parcel loses half its molecules when depressurised: for a fixed parcel, its reservoir-state volume would also change. Real Z can change with pressure, so the fixed-Z comparison is deliberately restricted.
Now leave the original gas inventory unchanged and change only the standard temperature, retaining pstd and Zstd = 1.
| Reporting temperature | Relation to the original Vstd | Approximate reported volume |
|---|---|---|
| 288.15 K | Original basis | 542 million m³ at 101,325 Pa and 288.15 K |
| 273.15 K | Multiply by 273.15 / 288.15 | 513 million m³ at 101,325 Pa and 273.15 K |
The smaller second number is a reporting-state change. Calling it a loss of gas would confuse a volume convention with a material balance.
CHAPTER 7 OF 12 · Change the conditions
7. Know when a two-state gas ratio is insufficient
The derivation holds n fixed between the two gas states. A fluid that releases dissolved gas, forms condensate, exchanges material with another phase or changes composition needs an appropriate phase-behaviour and component accounting model. Do not silently count all reservoir hydrocarbons as one unchanged gas parcel.
Likewise, a measured Bg belongs to its fluid and conditions. It should not be transferred from another field because its numerical size looks plausible. SLB’s PVT studies overview explains the role of measured fluid properties, phase behaviour and separation tests.
For a heterogeneous reservoir, multiplying independent-looking average inputs may also fail. A defensible spatial calculation respects the joint distribution of net volume, porosity, saturation and the relevant fluid-state factor.
CHAPTER 8 OF 12 · Check the evidence
8. Catch the mistakes before trusting the total
Pressure must be absolute. A gauge reading measures pressure relative to its reference atmosphere and must be converted consistently before entering pV = ZnRT. At low pressures, ignoring that offset can be especially consequential.
Temperature ratios require kelvin, not degrees Celsius. The example’s 350 K is 76.85°C, but 76.85 / 15 is not a substitute for 350 / 288.15. Celsius has an offset origin, so its ratios do not preserve the gas relation.
Finally, distinguish gas saturation from hydrocarbon saturation in a multiphase case, net from gross thickness, Bg from its reciprocal, and an in-place quantity from a recoverable quantity. A dimensionally tidy answer can still describe the wrong physical quantity.
Keep a short input sheet with the mapped area, thickness basis, porosity definition, saturation interpretation, pressure reference, temperature, composition, Z or measured Bg, and standard-state convention. Record which inputs are measured, modelled or assumed.
Check the limiting behaviour: at otherwise equal conditions, increasing pres decreases Bg; increasing Tres increases it. If both states have identical p, T and Z, Bg must equal one. These checks expose inversions without requiring another spreadsheet.
Report sensitivity without pretending that every extreme combination is equally plausible. Geological properties and fluid states can be related. A broad numerical range does not replace a justified reservoir model, and a single precise-looking total does not measure its uncertainty.
Is a standard cubic metre a different geometric unit?
It is still a cubic metre. The added condition identifies the gas state at which that volume represents an amount. Omitting the state discards information needed for a meaningful gas comparison.
Can I use Z = 1 everywhere?
Only where an ideal-gas approximation is justified for the required accuracy. Here Zres = 0.90 is supplied as a fictional input, not inferred from pressure alone. The relevant composition and PVT evidence determine a real value.
Does a gas-in-place estimate establish reserves?
No. It describes an inventory under the geological and fluid assumptions. Recovery, project feasibility and applicable resource-classification requirements require additional evidence. The subject root explains those distinctions.
Case A: retain the original geometry and fluid state but change gas saturation from 0.80 to 0.60. Gas-filled pore volume becomes 2,250,000 reservoir m³. Dividing by the same Bg gives about 406 million standard m³. The result is three quarters of the original because only Sg changed.
Case B: a report gives Bg = 0.006 reservoir m³ per standard m³ and Vstd = 100 million standard m³. Find the occupied reservoir volume. Multiplication gives 600,000 reservoir m³. Explain why division, correct for the earlier direction, would be wrong here.
Case C: a supposed “standard volume” changes from 542 million to 513 million m³ after a reporting-temperature revision. Before interpreting production or leakage, ask whether the pressure, temperature, Z convention and gas amount are the same. This is a transfer check: identify what changed before calculating what it means.
CHAPTER 12 OF 12 · Practise and continue
12. Continue from storage to defensible decisions
Geological storage and flow
Return to the Petroleum Geology root for source, reservoir, seal, timing and resource classifications. Use permeability, Darcy and hydraulic-conductivity terminology to keep occupied pore space separate from ease of flow.
Engineering interpretation
Continue to Petroleum Engineering: reservoir decisions, well integrity and responsible closure for the wider decision context. This conversion exercise supplies no operating procedure or field-specific recovery forecast.
The wider learning route
The Gold Standard of Education connects a calculation to reasoning that survives changed conditions. How X Works opens the wider subject directory. The practical habit to carry forward is simple: attach a state to the volume before treating it as an amount.
Sources checked 21 October 2026. Worked examples are educational models with the assumptions stated above.
