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Choose a route or read from the beginning. All teaching chapters stay open; the grouped index below is expandable.
Understand the clock
Chapters 1–2. Connect pulse identity, delay and the ambiguity interval.
Resolve a candidate
Chapters 3–5. Compare two trains and state the range of uniqueness.
Test the evidence
Chapters 6–8. Include uncertainty, association and separate radar limits.
Change and verify
Chapters 9–10. Alter the intervals and build an honest test record.
Practise and continue
Chapters 11–12. Check new targets and choose a specialist route.
Full chapter index · Practice and worked checks · Radar subject root
A radar return arrives 600 microseconds after the latest transmitted pulse. That delay suggests 90 kilometres in a simple round-trip calculation. But an older pulse may have produced the return. If pulses repeat every 1,000 microseconds, the same recorded delay could belong to a target at 240 kilometres, 390 kilometres or farther away.
The timing can be precise while the pulse identity remains ambiguous. This guide works through that distinction, then uses two different uniform pulse intervals to narrow the candidate ranges. The examples are invented, stationary-target calculations. They illustrate the reasoning behind ambiguity resolution, not a complete radar processor or a procedure for operating surveillance equipment.
Chapter index
Understand the clock · Chapters 1–2
1. Identify which pulse starts the clock
2. Derive the unambiguous range interval
Resolve a candidate · Chapters 3–5
3. Work through one distant stationary target
4. Add a second pulse interval without changing the target
5. State the range over which the answer is unique
Test the evidence · Chapters 6–8
6. Allow measurement intervals instead of exact numbers
7. Check that both returns belong to the same target
8. Separate range ambiguity from resolution and Doppler aliasing
Change and verify · Chapters 9–10
9. Change the intervals and inspect the new ambiguity pattern
10. Build a practical verification record
Practise and continue · Chapters 11–12
11. Practice with worked checks
12. Questions, connected routes and sources
In the simplified monostatic model, a pulse travels from the radar to a target and back to the same radar. Range R and round-trip delay τ are related by R = cτ/2. We use c = 300,000,000 metres per second as a convenient approximation for this air-path teaching model.
One microsecond of round-trip time therefore corresponds to 150 metres of one-way range. A delay of 600 microseconds gives 90,000 metres, or 90 kilometres, if it is measured from the pulse that actually produced the echo.
That last condition carries the problem. Suppose pulses are indistinguishable and occur every 1,000 microseconds. An echo arriving 1,600 microseconds after an earlier pulse arrives only 600 microseconds after the next pulse. A processor using the most recent pulse as its reference can assign the wrong range.
Draw the transmission marks and the return on the same time axis. The receiver records an arrival. Determining which transmission caused it is an additional inference.
Let T be the pulse repetition interval, the time between pulses in a uniform train. The corresponding range interval is U = cT/2. For T = 1,000 microseconds, U is 150 kilometres. Pulse repetition frequency is 1/T, so this interval corresponds to 1,000 pulses per second.
Under the simplified folding model, a return gives a remainder r between zero and U. The possible true ranges are R = r + kU for non-negative integers k. The integer identifies how many complete repetition intervals lie inside the round-trip delay.
The first interval, 0 ≤ R < U, contains one candidate per recorded remainder. Beyond it, ranges repeat in the same timing position. This is range ambiguity, also called range folding in appropriate radar contexts.
U is an ambiguity interval, not a guarantee of detection out to that distance and not a wall beyond which electromagnetic signals vanish. Signal strength, propagation, receiver timing and processing impose other conditions. A complete range claim must keep those separate.
CHAPTER 3 OF 12 · Resolve a candidate
3. Work through one distant stationary target
Choose a fictional target at 240 kilometres. Its round-trip distance is 480 kilometres. Dividing by our stated propagation speed gives 1,600 microseconds.
In a steady 1,000-microsecond pulse train, the delay remainder is 600 microseconds. The naive display range is therefore 90 kilometres. The missing interval corresponds to another 150 kilometres: 90 + 150 = 240.
| True range candidate | Round-trip delay | Delay remainder with T = 1,000 μs |
|---|---|---|
| 90 km | 600 μs | 600 μs |
| 240 km | 1,600 μs | 600 μs |
| 390 km | 2,600 μs | 600 μs |
| 540 km | 3,600 μs | 600 μs |
Every row matches the recorded timing remainder. Choosing 90 kilometres because it is the smallest value supplies an extra assumption: the target lies in the first interval. That assumption needs support.
The example assumes established pulse trains, usable received echoes and no identifying pulse coding. Start-up behaviour, receiver blanking or a tagged waveform can add information not represented by the remainder-only model.
CHAPTER 4 OF 12 · Resolve a candidate
4. Add a second pulse interval without changing the target
Now observe the same stationary target in another uniform pulse train with T = 1,200 microseconds. Its ambiguity interval is U = 180 kilometres. The true round-trip delay remains 1,600 microseconds because the target has not moved.
The new remainder is 400 microseconds, corresponding to 60 kilometres. The first observation produced candidates 90, 240, 390, 540 and so on. The second produces 60, 240, 420, 600 and so on.
If a separately justified search region is 0 ≤ R < 600 kilometres, the first list contains 90, 240, 390 and 540; the second contains 60, 240 and 420. Their sole shared candidate is 240 kilometres.
The extra observation helps because the ambiguity pattern changed while the target range stayed fixed. Repeating the original interval would reproduce the same candidate list.
These are two separate uniform trains. An alternating pulse schedule has a different timing history and must be modelled from its actual transmission times; it should not automatically be treated as two independent remainder measurements.
CHAPTER 5 OF 12 · Resolve a candidate
5. State the range over which the answer is unique
Solving 90 + 150k = 60 + 180j gives 5k − 6j = −1. One solution is k = j = 1, yielding 240 kilometres. Another is k = 7 and j = 6, yielding 1,140 kilometres.
The ambiguity pattern repeats every 900 kilometres because 900 is the least positive common multiple of 150 and 180 in this exact, commensurate example. Thus 240, 1,140 and 2,040 kilometres all fit the two ideal remainders.
Two observations have extended the interval of uniqueness; they have not established a unique range across every imaginable distance. A stated bound such as 0 ≤ R < 900 kilometres admits only 240 kilometres. A larger admissible region may admit more candidates.
The bound must come from physical or independently justified information. Selecting a bound only because it preserves the desired answer would be circular. Record both the candidate intersection and the basis for excluding other intersections. The distinction matters whenever a mathematically exact reconstruction hides an unstated search region.
CHAPTER 6 OF 12 · Test the evidence
6. Allow measurement intervals instead of exact numbers
Real timing estimates have uncertainty. Suppose the first apparent range is 90.0 ± 0.6 kilometres and the second is 60.0 ± 0.6 kilometres. Treat these as stated admissible error bands for this exercise, not statistical confidence intervals.
The candidate near 240 kilometres from the first measurement spans 239.4 to 240.6 kilometres. The candidate from the second spans the same interval. Their overlap supports a range band rather than an exact 240.000-kilometre claim.
Now change the second reading to 61.0 ± 0.6 kilometres. Its candidate near the same trip is 240.4 to 241.6 kilometres. The overlap with the first becomes 240.4 to 240.6 kilometres. If the second reading were 62.0 ± 0.6 instead, those particular bands would not overlap.
A non-overlap is a reason to investigate the model, association and error assumptions. It is not an instruction to average incompatible candidates. Real estimators need a justified uncertainty model, including timing calibration and dependence between observations. The simple bands only make the logical issue visible.
CHAPTER 7 OF 12 · Test the evidence
7. Check that both returns belong to the same target
Candidate intersection assumes correct association. Consider two stationary targets at 60 and 90 kilometres. Both lie in the first interval of both pulse trains, so both observations contain returns at 60 and 90 kilometres.
If a processor incorrectly pairs the 90-kilometre return from the first train with the 60-kilometre return from the second, the earlier intersection calculation suggests 240 kilometres. There need not be any target there. The arithmetic is consistent with the pair; the pair itself is wrong.
A useful processor therefore needs evidence for association, potentially drawing on angle, motion, return structure and observations over time. These cues have their own limitations. Matching a convenient amplitude or a nearby plotted position does not automatically establish identity.
Keep two questions separate in the report: which range candidates fit a proposed pair, and why should those observations be paired? A correct answer to the first cannot repair missing evidence for the second. The sensor-fusion and tracking guides provide wider context for this information problem.
CHAPTER 8 OF 12 · Test the evidence
8. Separate range ambiguity from resolution and Doppler aliasing
Range resolution concerns distinguishing nearby returns in range. Range ambiguity concerns multiple possible ranges for a recorded timing pattern. A return can be sharply localised within its apparent bin and still have the wrong trip assignment.
Doppler ambiguity concerns the interpretation of sampled phase change and radial velocity. Changing pulse repetition frequency affects that sampling as well as the range interval. The familiar range–velocity tradeoff is one reason waveform and processing choices need system-level analysis.
Our two-interval calculation resolves an ideal range candidate under stated conditions. It does not demonstrate unambiguous velocity, good two-target resolution or a particular detection probability. Those are separate tests.
The existing radar mathematics article introduces repetition limits and velocity aliasing. Here the added work is the explicit candidate lists, their repeated intersections, noisy bands and false pairings. Use the question being answered to select the calculation, rather than treating every radar limit as one interchangeable “accuracy” number.
CHAPTER 9 OF 12 · Change and verify
9. Change the intervals and inspect the new ambiguity pattern
For a transfer example, keep the target at 240 kilometres but use repetition intervals of 800 and 1,000 microseconds. Their range intervals are 120 and 150 kilometres.
The ideal apparent ranges are zero and 90 kilometres: 240 is an exact multiple of 120, while 240 − 150 = 90. The candidate lists intersect at 240, then 840 kilometres, repeating every 600 kilometres.
An apparent zero is a mathematical remainder here. It does not prove that an actual receiver could observe an echo coincident with transmission. Receiver blanking and recovery can make such timing unusable. This physical limitation belongs beside the arithmetic.
Changing intervals changes both the candidate pattern and the practical observation conditions. A longer theoretical interval of uniqueness is useful only when the required returns can be detected, associated and measured. Choosing periods solely by a least-common-multiple calculation leaves those engineering questions unanswered.
A paper investigation can use supplied transmit times and synthetic arrival records. Record the pulse intervals in seconds, convert them to ambiguity intervals, list all candidates inside a stated region and mark every surviving intersection. Preserve discarded candidates and the reason for discarding them.
Use a synthetic truth table that includes an ordinary first-trip target, a farther target, two targets that could be mispaired, a missing return and a deliberately inconsistent timing measurement. The truth is known because the examples were constructed. Compare the method’s decisions with that truth.
Report unresolved cases explicitly. A method that sometimes declines to assign a trip can be more informative than one that silently chooses the smallest range every time. Count wrong assignments separately from missing or unresolved observations.
This activity needs no radio transmitter. A spreadsheet or hand calculation is enough to practise the inference. Actual radar validation requires representative propagation, targets, interference and system behaviour, well beyond this ideal timing exercise.
Check one: another range in the same interval
With ambiguity intervals 150 and 180 kilometres, a target at 420 kilometres produces apparent ranges of 120 and 60 kilometres. The lists 120 + 150k and 60 + 180j share 420 kilometres inside 0 ≤ R < 900 kilometres. Substitute 420 into both remainder calculations as a reverse check.
Check two: the recurring alias
For the original apparent pair of 90 and 60 kilometres, test 1,140 kilometres. Subtracting seven 150-kilometre intervals gives 90; subtracting six 180-kilometre intervals gives 60. The pair fits. It is excluded by a justified 900-kilometre search bound, not by the timing equations themselves.
Check three: identify the missing assumption
A report says: “Two pulse intervals gave one match, therefore the target is certainly at 240 kilometres.” Ask for the search region, timing uncertainty and association evidence. Without those, the statement goes beyond the calculation. Rewrite it as a conditional result with the surviving candidate and its stated limits.
CHAPTER 12 OF 12 · Practise and continue
12. Questions, connected routes and sources
Does a folded range mean the radar clock is inaccurate?
No. Accurate arrival timing can coexist with uncertain transmission identity. Calibration and ambiguity are different questions.
Can two pulse intervals always resolve range?
No. Multiple intersections, uncertain measurements, false associations and missing returns can leave ambiguity. Our uniqueness statement depends on a bounded ideal model.
Does a smaller displayed range prove a closer target?
Only after the relevant ambiguity and processing have been addressed. A remainder-only display need not preserve the true ordering of targets.
Where should I continue?
For signal timing and geometry, return to The Gold Standard of Radar and radar range, angles and Doppler mathematics. For different limitations, read weak echoes beside strong targets and out-of-order observations and track age.
For association and system evidence, continue with sensor fusion engineering. For an application whose interpretation depends on sampling, use weather-radar reflectivity and rainfall estimation. The Gold Standard of Education and How X Works provide the wider learning routes.
The US National Weather Service’s Doppler Radar Guide, second edition explains multiple-trip range folding and Doppler aliasing. Its radar fundamentals training covers pulse timing. MIT Lincoln Laboratory’s Introduction to Radar Systems provides a broader technical course. These are educational sources; the synthetic two-train calculations above are not claims about a current operational configuration.
Sources checked 21 October 2026. Worked examples are educational models with the assumptions stated above.